2022-01-25

Two angle bisectors and one altitude in a right angled triangle

This question was uploaded on 25/01/22 on social media accounts.

Solution:

Given that, a:b = 3:4
Let AB = 15 and BC = 20 so AC = 25, AE = 9, CE = 16

2x + 2y = 90  (or)  x + y = 45
<BDC = 90 - x = x + 2y
<BFA = 90 - y = 2x + y
By this, Triangles ABF and CBD are isosceles.
So, AF = 15 and CD = 20
Also, AD = 5 and FC = 10

Now, DE = AE - AD = 9 - 5 = 4
and, FE = CE - CF = 16 - 10 = 6

c:d = DE:FE = 4:6 = 2:3
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